x^2+3x-0.64=0

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Solution for x^2+3x-0.64=0 equation:



x^2+3x-0.64=0
a = 1; b = 3; c = -0.64;
Δ = b2-4ac
Δ = 32-4·1·(-0.64)
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{11.56}}{2*1}=\frac{-3-\sqrt{11.56}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{11.56}}{2*1}=\frac{-3+\sqrt{11.56}}{2} $

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